A body thrown vertically upwards with an initial velocity u reaches maximum height in 6 seconds. The ratio of the distances travelled by the body in the first second and the seventh second is
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Time of ascent \(= \frac{u}{g} = 6 \text{ sec} \Rightarrow u = 60 \, m/s\)
Distance in first second \(h_{\text{first}} = 60 - \frac{g}{2} (2 \times 1 - 1) = 55 \, m\)
Distance in seventh second will be equal to the distance in first second of vertical downward motion \(h_{\text{seventh}} = \frac{g}{2} (2 \times 3 - 1) = 5m\) ⇒ ⇒ \(h_{\text{first}} / h_{\text{seventh}}\) \(= 11 \cdot 1\)
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